Base | Representation |
---|---|
bin | 11010101010000111… |
… | …11101001111001111 |
3 | 1100221102120001120002 |
4 | 31111003331033033 |
5 | 213302333040021 |
6 | 10324055514515 |
7 | 1014444004562 |
oct | 152503751717 |
9 | 40842501502 |
10 | 14312002511 |
11 | 6084830354 |
12 | 2935088a3b |
13 | 147114cb51 |
14 | 99aad24d9 |
15 | 58b71350b |
hex | 3550fd3cf |
14312002511 has 2 divisors, whose sum is σ = 14312002512. Its totient is φ = 14312002510.
The previous prime is 14312002403. The next prime is 14312002519. The reversal of 14312002511 is 11520021341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14312002511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14312002519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156001255 + 7156001256.
It is an arithmetic number, because the mean of its divisors is an integer number (7156001256).
Almost surely, 214312002511 is an apocalyptic number.
14312002511 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312002511 is an equidigital number, since it uses as much as digits as its factorization.
14312002511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 14312002511 its reverse (11520021341), we get a palindrome (25832023852).
The spelling of 14312002511 in words is "fourteen billion, three hundred twelve million, two thousand, five hundred eleven".
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