Base | Representation |
---|---|
bin | 100000100010101010111010… |
… | …110010100001000111001001 |
3 | 200202202010211020201221211011 |
4 | 200202222322302201013021 |
5 | 122224334312203323223 |
6 | 1224220234100403521 |
7 | 42101036602051246 |
oct | 4042527262410711 |
9 | 622663736657734 |
10 | 143120034042313 |
11 | 416699580a3589 |
12 | 140757559a65a1 |
13 | 61b22134b6833 |
14 | 274b091c6c5cd |
15 | 1182d31bac80d |
hex | 822abaca11c9 |
143120034042313 has 2 divisors, whose sum is σ = 143120034042314. Its totient is φ = 143120034042312.
The previous prime is 143120034042299. The next prime is 143120034042329. The reversal of 143120034042313 is 313240430021341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120357860217529 + 22762173824784 = 10970773^2 + 4770972^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143120034042313 is a prime.
It is not a weakly prime, because it can be changed into another prime (143120034042353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560017021156 + 71560017021157.
It is an arithmetic number, because the mean of its divisors is an integer number (71560017021157).
Almost surely, 2143120034042313 is an apocalyptic number.
It is an amenable number.
143120034042313 is a deficient number, since it is larger than the sum of its proper divisors (1).
143120034042313 is an equidigital number, since it uses as much as digits as its factorization.
143120034042313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 143120034042313 its reverse (313240430021341), we get a palindrome (456360464063654).
The spelling of 143120034042313 in words is "one hundred forty-three trillion, one hundred twenty billion, thirty-four million, forty-two thousand, three hundred thirteen".
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