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143120034042313 is a prime number
BaseRepresentation
bin100000100010101010111010…
…110010100001000111001001
3200202202010211020201221211011
4200202222322302201013021
5122224334312203323223
61224220234100403521
742101036602051246
oct4042527262410711
9622663736657734
10143120034042313
11416699580a3589
12140757559a65a1
1361b22134b6833
14274b091c6c5cd
151182d31bac80d
hex822abaca11c9

143120034042313 has 2 divisors, whose sum is σ = 143120034042314. Its totient is φ = 143120034042312.

The previous prime is 143120034042299. The next prime is 143120034042329. The reversal of 143120034042313 is 313240430021341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120357860217529 + 22762173824784 = 10970773^2 + 4770972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143120034042313 is a prime.

It is not a weakly prime, because it can be changed into another prime (143120034042353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560017021156 + 71560017021157.

It is an arithmetic number, because the mean of its divisors is an integer number (71560017021157).

Almost surely, 2143120034042313 is an apocalyptic number.

It is an amenable number.

143120034042313 is a deficient number, since it is larger than the sum of its proper divisors (1).

143120034042313 is an equidigital number, since it uses as much as digits as its factorization.

143120034042313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 143120034042313 its reverse (313240430021341), we get a palindrome (456360464063654).

The spelling of 143120034042313 in words is "one hundred forty-three trillion, one hundred twenty billion, thirty-four million, forty-two thousand, three hundred thirteen".