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14312012410034 = 259272834445561
BaseRepresentation
bin1101000001000100011001…
…1010100110110010110010
31212200012210202022122012222
43100101012122212302302
53333442000134110114
650234503035521042
73005003003154503
oct320210632466262
955605722278188
1014312012410034
11461876598a389
12173191bbb9182
137ca803670b91
143769c2adcbaa
1519c44ce7e98e
hexd04466a6cb2

14312012410034 has 16 divisors (see below), whose sum is σ = 21832688449440. Its totient is φ = 7034458539360.

The previous prime is 14312012410021. The next prime is 14312012410037. The reversal of 14312012410034 is 43001421021341.

It is a junction number, because it is equal to n+sod(n) for n = 14312012409985 and 14312012410012.

It is not an unprimeable number, because it can be changed into a prime (14312012410037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 996614 + ... + 5442174.

It is an arithmetic number, because the mean of its divisors is an integer number (1364543028090).

Almost surely, 214312012410034 is an apocalyptic number.

14312012410034 is a deficient number, since it is larger than the sum of its proper divisors (7520676039406).

14312012410034 is a wasteful number, since it uses less digits than its factorization.

14312012410034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4472905.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14312012410034 its reverse (43001421021341), we get a palindrome (57313433431375).

The spelling of 14312012410034 in words is "fourteen trillion, three hundred twelve billion, twelve million, four hundred ten thousand, thirty-four".

Divisors: 1 2 59 118 27283 54566 1609697 3219394 4445561 8891122 262288099 524576198 121288240763 242576481526 7156006205017 14312012410034