14312110141 has 4 divisors (see below), whose sum is σ = 16356697312. Its totient is φ = 12267522972.

The previous prime is 14312110139. The next prime is 14312110147. The reversal of 14312110141 is 14101121341.

14312110141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14312110141 - 2¹ = 14312110139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312110147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1022293575 + ... + 1022293588.

It is an arithmetic number, because the mean of its divisors is an integer number (4089174328).

Almost surely, 2^14312110141 is an apocalyptic number.

It is an amenable number.

14312110141 is a deficient number, since it is larger than the sum of its proper divisors (2044587171).

14312110141 is an equidigital number, since it uses as much as digits as its factorization.

14312110141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2044587170.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 14312110141 its reverse (14101121341), we get a palindrome (28413231482).

The spelling of 14312110141 in words is "fourteen billion, three hundred twelve million, one hundred ten thousand, one hundred forty-one".