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14312121423 = 34770707141
BaseRepresentation
bin11010101010001000…
…11010010001001111
31100221102210002200020
431111010122101033
5213302400341143
610324102233223
71014445011345
oct152504322117
940842702606
1014312121423
116084901726
122935125813
131471192002
1499ab23995
1558b738883
hex35511a44f

14312121423 has 4 divisors (see below), whose sum is σ = 19082828568. Its totient is φ = 9541414280.

The previous prime is 14312121407. The next prime is 14312121437. The reversal of 14312121423 is 32412121341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14312121423 - 24 = 14312121407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14312121393 and 14312121402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312121023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385353568 + ... + 2385353573.

It is an arithmetic number, because the mean of its divisors is an integer number (4770707142).

Almost surely, 214312121423 is an apocalyptic number.

14312121423 is a deficient number, since it is larger than the sum of its proper divisors (4770707145).

14312121423 is an equidigital number, since it uses as much as digits as its factorization.

14312121423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4770707144.

The product of its digits is 1152, while the sum is 24.

Adding to 14312121423 its reverse (32412121341), we get a palindrome (46724242764).

The spelling of 14312121423 in words is "fourteen billion, three hundred twelve million, one hundred twenty-one thousand, four hundred twenty-three".

Divisors: 1 3 4770707141 14312121423