14312122431 has 4 divisors (see below), whose sum is σ = 19082829912. Its totient is φ = 9541414952.

The previous prime is 14312122417. The next prime is 14312122441. The reversal of 14312122431 is 13422121341.

14312122431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14312122431 - 2⁷ = 14312122303 is a prime.

It is a super-2 number, since 2×14312122431² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312122411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385353736 + ... + 2385353741.

It is an arithmetic number, because the mean of its divisors is an integer number (4770707478).

Almost surely, 2^14312122431 is an apocalyptic number.

14312122431 is a deficient number, since it is larger than the sum of its proper divisors (4770707481).

14312122431 is an equidigital number, since it uses as much as digits as its factorization.

14312122431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4770707480.

The product of its digits is 1152, while the sum is 24.

Adding to 14312122431 its reverse (13422121341), we get a palindrome (27734243772).

The spelling of 14312122431 in words is "fourteen billion, three hundred twelve million, one hundred twenty-two thousand, four hundred thirty-one".