14312134044 has 72 divisors (see below), whose sum is σ = 39128321232. Its totient is φ = 4384800000.

The previous prime is 14312134043. The next prime is 14312134051. The reversal of 14312134044 is 44043121341.

14312134044 is a `hidden beast` number, since 1 + 4 + 312 + 1 + 340 + 4 + 4 = 666.

14312134044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 14312133999 and 14312134017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312134043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 43419 + ... + 174669.

It is an arithmetic number, because the mean of its divisors is an integer number (543448906).

Almost surely, 2^14312134044 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14312134044, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19564160616).

14312134044 is an abundant number, since it is smaller than the sum of its proper divisors (24816187188).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14312134044 is a wasteful number, since it uses less digits than its factorization.

14312134044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131507 (or 131502 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 14312134044 its reverse (44043121341), we get a palindrome (58355255385).

The spelling of 14312134044 in words is "fourteen billion, three hundred twelve million, one hundred thirty-four thousand, forty-four".