Base | Representation |
---|---|
bin | 1000010101001010110… |
… | …0110100001000011111 |
3 | 111200102101011110001121 |
4 | 2011102230310020133 |
5 | 4321103034302401 |
6 | 145425444151411 |
7 | 13224452554606 |
oct | 2052254641037 |
9 | 450371143047 |
10 | 143121400351 |
11 | 55774332456 |
12 | 238a3098567 |
13 | 1065b470957 |
14 | 6cd9dd6a3d |
15 | 3ac9c95ca1 |
hex | 2152b3421f |
143121400351 has 12 divisors (see below), whose sum is σ = 152127469312. Its totient is φ = 134621042688.
The previous prime is 143121400333. The next prime is 143121400369. The reversal of 143121400351 is 153004121341.
It is an interprime number because it is at equal distance from previous prime (143121400333) and next prime (143121400369).
It is a de Polignac number, because none of the positive numbers 2k-143121400351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143121400381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 331711 + ... + 629503.
Almost surely, 2143121400351 is an apocalyptic number.
143121400351 is a deficient number, since it is larger than the sum of its proper divisors (9006068961).
143121400351 is a wasteful number, since it uses less digits than its factorization.
143121400351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 299490 (or 299473 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 143121400351 its reverse (153004121341), we get a palindrome (296125521692).
The spelling of 143121400351 in words is "one hundred forty-three billion, one hundred twenty-one million, four hundred thousand, three hundred fifty-one".
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