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14312200403 is a prime number
BaseRepresentation
bin11010101010001001…
…01101100011010011
31100221102221010000102
431111010231203103
5213302410403103
610324104043015
71014445460534
oct152504554323
940842833012
1014312200403
116084955aa6
12293516346b
1314711bbc47
1499ab4468b
1558b751e88
hex35512d8d3

14312200403 has 2 divisors, whose sum is σ = 14312200404. Its totient is φ = 14312200402.

The previous prime is 14312200393. The next prime is 14312200439. The reversal of 14312200403 is 30400221341.

14312200403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14312200403 - 24 = 14312200387 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (14312200003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156100201 + 7156100202.

It is an arithmetic number, because the mean of its divisors is an integer number (7156100202).

Almost surely, 214312200403 is an apocalyptic number.

14312200403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312200403 is an equidigital number, since it uses as much as digits as its factorization.

14312200403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 14312200403 its reverse (30400221341), we get a palindrome (44712421744).

The spelling of 14312200403 in words is "fourteen billion, three hundred twelve million, two hundred thousand, four hundred three".