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143122034143 = 11101128822713
BaseRepresentation
bin1000010101001010111…
…1001110110111011111
3111200102102100122110101
42011102233032313133
54321103220043033
6145425505521531
713224461134444
oct2052257166737
9450372318411
10143122034143
1155774725650
12238a33432a7
131065b63328a
146cda11d9cb
153ac9d6d97d
hex2152bceddf

143122034143 has 8 divisors (see below), whose sum is σ = 157679001936. Its totient is φ = 128822712000.

The previous prime is 143122034137. The next prime is 143122034189. The reversal of 143122034143 is 341430221341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143122034143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143122034113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64410246 + ... + 64412467.

It is an arithmetic number, because the mean of its divisors is an integer number (19709875242).

Almost surely, 2143122034143 is an apocalyptic number.

143122034143 is a deficient number, since it is larger than the sum of its proper divisors (14556967793).

143122034143 is a wasteful number, since it uses less digits than its factorization.

143122034143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128822825.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 143122034143 its reverse (341430221341), we get a palindrome (484552255484).

The spelling of 143122034143 in words is "one hundred forty-three billion, one hundred twenty-two million, thirty-four thousand, one hundred forty-three".

Divisors: 1 11 101 1111 128822713 1417049843 13011094013 143122034143