1431221131 has 2 divisors, whose sum is σ = 1431221132. Its totient is φ = 1431221130.

The previous prime is 1431221123. The next prime is 1431221149. The reversal of 1431221131 is 1311221341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1431221131 - 2³ = 1431221123 is a prime.

It is a super-2 number, since 2×1431221131² = 4096787851641838322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1431221099 and 1431221108.

It is not a weakly prime, because it can be changed into another prime (1431221191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715610565 + 715610566.

It is an arithmetic number, because the mean of its divisors is an integer number (715610566).

Almost surely, 2^1431221131 is an apocalyptic number.

1431221131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431221131 is an equidigital number, since it uses as much as digits as its factorization.

1431221131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 1431221131 is about 37831.4833306864. The cubic root of 1431221131 is about 1126.9437687851.

Adding to 1431221131 its reverse (1311221341), we get a palindrome (2742442472).

The spelling of 1431221131 in words is "one billion, four hundred thirty-one million, two hundred twenty-one thousand, one hundred thirty-one".