Base | Representation |
---|---|
bin | 10100110100111011011… |
… | …111011111101000011101 |
3 | 12001211020100002222100001 |
4 | 110310323133133220131 |
5 | 141422120342040331 |
6 | 3013254443134301 |
7 | 205255010104303 |
oct | 24647337375035 |
9 | 5054210088301 |
10 | 1431222221341 |
11 | 501a836a5300 |
12 | 1b1469514391 |
13 | a4c6b273963 |
14 | 4d3b30ca273 |
15 | 27369213561 |
hex | 14d3b7dfa1d |
1431222221341 has 48 divisors (see below), whose sum is σ = 1609883412480. Its totient is φ = 1271160633600.
The previous prime is 1431222221329. The next prime is 1431222221389.
1431222221341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1431222221341 - 231 = 1429074737693 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1431222221321) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 368774721 + ... + 368778601.
It is an arithmetic number, because the mean of its divisors is an integer number (33539237760).
Almost surely, 21431222221341 is an apocalyptic number.
1431222221341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1431222221341 is a deficient number, since it is larger than the sum of its proper divisors (178661191139).
1431222221341 is a wasteful number, since it uses less digits than its factorization.
1431222221341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4378 (or 4367 counting only the distinct ones).
The product of its digits is 4608, while the sum is 28.
The spelling of 1431222221341 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-two million, two hundred twenty-one thousand, three hundred forty-one".
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