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14312223453 = 311433703741
BaseRepresentation
bin11010101010001001…
…10011001011011101
31100221102222021122010
431111010303023131
5213302412122303
610324104341433
71014445614663
oct152504631335
940842867563
1014312223453
116084971350
122935174879
1314711c9598
1499ab4cc33
1558b758c03
hex3551332dd

14312223453 has 8 divisors (see below), whose sum is σ = 20817779616. Its totient is φ = 8674074800.

The previous prime is 14312223451. The next prime is 14312223493. The reversal of 14312223453 is 35432221341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14312223453 - 21 = 14312223451 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14312223453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312223451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216851838 + ... + 216851903.

It is an arithmetic number, because the mean of its divisors is an integer number (2602222452).

Almost surely, 214312223453 is an apocalyptic number.

It is an amenable number.

14312223453 is a deficient number, since it is larger than the sum of its proper divisors (6505556163).

14312223453 is a wasteful number, since it uses less digits than its factorization.

14312223453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433703755.

The product of its digits is 17280, while the sum is 30.

Adding to 14312223453 its reverse (35432221341), we get a palindrome (49744444794).

The spelling of 14312223453 in words is "fourteen billion, three hundred twelve million, two hundred twenty-three thousand, four hundred fifty-three".

Divisors: 1 3 11 33 433703741 1301111223 4770741151 14312223453