Base | Representation |
---|---|
bin | 11010101010001001… |
… | …10111100001001111 |
3 | 1100221110000012000120 |
4 | 31111010313201033 |
5 | 213302413204411 |
6 | 10324105000023 |
7 | 1014446020551 |
oct | 152504674117 |
9 | 40843005016 |
10 | 14312241231 |
11 | 6084983742 |
12 | 2935183013 |
13 | 14712046c2 |
14 | 99ab554d1 |
15 | 58b75e106 |
hex | 35513784f |
14312241231 has 24 divisors (see below), whose sum is σ = 20878404912. Its totient is φ = 8690515200.
The previous prime is 14312241199. The next prime is 14312241233. The reversal of 14312241231 is 13214221341.
It is not a de Polignac number, because 14312241231 - 25 = 14312241199 is a prime.
It is a super-2 number, since 2×143122412312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14312241233) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 97000 + ... + 195021.
It is an arithmetic number, because the mean of its divisors is an integer number (869933538).
Almost surely, 214312241231 is an apocalyptic number.
14312241231 is a deficient number, since it is larger than the sum of its proper divisors (6566163681).
14312241231 is a wasteful number, since it uses less digits than its factorization.
14312241231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 292103 (or 292072 counting only the distinct ones).
The product of its digits is 1152, while the sum is 24.
Adding to 14312241231 its reverse (13214221341), we get a palindrome (27526462572).
The spelling of 14312241231 in words is "fourteen billion, three hundred twelve million, two hundred forty-one thousand, two hundred thirty-one".
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