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143123556231401 is a prime number
BaseRepresentation
bin100000100010101110001100…
…101110100110100011101001
3200202202110220201100200220212
4200202232030232212203221
5122224414020343401101
61224222015401230505
742101223101135144
oct4042561456464351
9622673821320825
10143123556231401
11416703a52a6359
1214076379492435
1361b2655121aa5
14274b30796505b
151182e8aeee1bb
hex822b8cba68e9

143123556231401 has 2 divisors, whose sum is σ = 143123556231402. Its totient is φ = 143123556231400.

The previous prime is 143123556231343. The next prime is 143123556231413. The reversal of 143123556231401 is 104132655321341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127851053151376 + 15272503080025 = 11307124^2 + 3908005^2 .

It is an emirp because it is prime and its reverse (104132655321341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143123556231401 - 210 = 143123556230377 is a prime.

It is not a weakly prime, because it can be changed into another prime (143123556231451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71561778115700 + 71561778115701.

It is an arithmetic number, because the mean of its divisors is an integer number (71561778115701).

Almost surely, 2143123556231401 is an apocalyptic number.

It is an amenable number.

143123556231401 is a deficient number, since it is larger than the sum of its proper divisors (1).

143123556231401 is an equidigital number, since it uses as much as digits as its factorization.

143123556231401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 143123556231401 in words is "one hundred forty-three trillion, one hundred twenty-three billion, five hundred fifty-six million, two hundred thirty-one thousand, four hundred one".