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143124041113612 = 22132331163197239503
BaseRepresentation
bin100000100010101110101001…
…101000010010000000001100
3200202202112011111202021021021
4200202232221220102000030
5122224421014011113422
61224222135442043524
742101241106435666
oct4042565150220014
9622675144667237
10143124041113612
1141670623a77559
12140764939495a4
1361b2701712a40
14274b352103536
151182eb887cdc7
hex822ba9a1200c

143124041113612 has 384 divisors, whose sum is σ = 295622926663680. Its totient is φ = 60090654919680.

The previous prime is 143124041113607. The next prime is 143124041113633. The reversal of 143124041113612 is 216311140421341.

It is a super-2 number, since 2×1431240411136122 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 284540836953 + ... + 284540837455.

It is an arithmetic number, because the mean of its divisors is an integer number (769851371520).

Almost surely, 2143124041113612 is an apocalyptic number.

It is an amenable number.

143124041113612 is an abundant number, since it is smaller than the sum of its proper divisors (152498885550068).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143124041113612 is a wasteful number, since it uses less digits than its factorization.

143124041113612 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1173 (or 1171 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 34.

Adding to 143124041113612 its reverse (216311140421341), we get a palindrome (359435181534953).

The spelling of 143124041113612 in words is "one hundred forty-three trillion, one hundred twenty-four billion, forty-one million, one hundred thirteen thousand, six hundred twelve".