Base | Representation |
---|---|
bin | 1000010101001011011… |
… | …1001100110110001011 |
3 | 111200102120021202212011 |
4 | 2011102313030312023 |
5 | 4321104233414034 |
6 | 145430022400351 |
7 | 13224514654453 |
oct | 2052267146613 |
9 | 450376252764 |
10 | 143124123019 |
11 | 55775921a99 |
12 | 238a3b900b7 |
13 | 1065bbb4cb7 |
14 | 6cda504d63 |
15 | 3aca132864 |
hex | 2152dccd8b |
143124123019 has 2 divisors, whose sum is σ = 143124123020. Its totient is φ = 143124123018.
The previous prime is 143124122971. The next prime is 143124123151. The reversal of 143124123019 is 910321421341.
143124123019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143124123019 - 27 = 143124122891 is a prime.
It is a super-2 number, since 2×1431241230192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (143124123319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562061509 + 71562061510.
It is an arithmetic number, because the mean of its divisors is an integer number (71562061510).
Almost surely, 2143124123019 is an apocalyptic number.
143124123019 is a deficient number, since it is larger than the sum of its proper divisors (1).
143124123019 is an equidigital number, since it uses as much as digits as its factorization.
143124123019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 143124123019 in words is "one hundred forty-three billion, one hundred twenty-four million, one hundred twenty-three thousand, nineteen".
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