Base | Representation |
---|---|
bin | 1000010101001011011… |
… | …1001111010101101111 |
3 | 111200102120022021212101 |
4 | 2011102313033111233 |
5 | 4321104234230411 |
6 | 145430022515531 |
7 | 13224515026312 |
oct | 2052267172557 |
9 | 450376267771 |
10 | 143124133231 |
11 | 55775929732 |
12 | 238a3b95ba7 |
13 | 1065bbb9841 |
14 | 6cda508979 |
15 | 3aca1358c1 |
hex | 2152dcf56f |
143124133231 has 32 divisors (see below), whose sum is σ = 153166464000. Its totient is φ = 133524623232.
The previous prime is 143124133219. The next prime is 143124133241. The reversal of 143124133231 is 132331421341.
It is a cyclic number.
It is not a de Polignac number, because 143124133231 - 25 = 143124133199 is a prime.
It is a super-2 number, since 2×1431241332312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 143124133231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143124133211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24096060 + ... + 24101998.
It is an arithmetic number, because the mean of its divisors is an integer number (4786452000).
Almost surely, 2143124133231 is an apocalyptic number.
143124133231 is a deficient number, since it is larger than the sum of its proper divisors (10042330769).
143124133231 is a wasteful number, since it uses less digits than its factorization.
143124133231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6271.
The product of its digits is 5184, while the sum is 28.
Adding to 143124133231 its reverse (132331421341), we get a palindrome (275455554572).
The spelling of 143124133231 in words is "one hundred forty-three billion, one hundred twenty-four million, one hundred thirty-three thousand, two hundred thirty-one".
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