14312440423 has 4 divisors (see below), whose sum is σ = 14616960480. Its totient is φ = 14007920368.

The previous prime is 14312440409. The next prime is 14312440453. The reversal of 14312440423 is 32404421341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14312440423 - 2¹³ = 14312432231 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14312440391 and 14312440400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14312440453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152259958 + ... + 152260051.

It is an arithmetic number, because the mean of its divisors is an integer number (3654240120).

Almost surely, 2^14312440423 is an apocalyptic number.

14312440423 is a deficient number, since it is larger than the sum of its proper divisors (304520057).

14312440423 is an equidigital number, since it uses as much as digits as its factorization.

14312440423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304520056.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 14312440423 its reverse (32404421341), we get a palindrome (46716861764).

The spelling of 14312440423 in words is "fourteen billion, three hundred twelve million, four hundred forty thousand, four hundred twenty-three".