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1431244133 = 11130113103
BaseRepresentation
bin101010101001111…
…0000110101100101
310200202010201211222
41111103300311211
510412344303013
6354004310125
750316242264
oct12523606545
93622121758
101431244133
116749999a0
1233b3a2345
1319a69ab27
14d81265db
15859b7508
hex554f0d65

1431244133 has 4 divisors (see below), whose sum is σ = 1561357248. Its totient is φ = 1301131020.

The previous prime is 1431244109. The next prime is 1431244169. The reversal of 1431244133 is 3314421341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431244133 - 210 = 1431243109 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431244193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65056541 + ... + 65056562.

It is an arithmetic number, because the mean of its divisors is an integer number (390339312).

Almost surely, 21431244133 is an apocalyptic number.

It is an amenable number.

1431244133 is a deficient number, since it is larger than the sum of its proper divisors (130113115).

1431244133 is a wasteful number, since it uses less digits than its factorization.

1431244133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130113114.

The product of its digits is 3456, while the sum is 26.

The square root of 1431244133 is about 37831.7873355198. The cubic root of 1431244133 is about 1126.9498060123.

Adding to 1431244133 its reverse (3314421341), we get a palindrome (4745665474).

The spelling of 1431244133 in words is "one billion, four hundred thirty-one million, two hundred forty-four thousand, one hundred thirty-three".

Divisors: 1 11 130113103 1431244133