Base | Representation |
---|---|
bin | 11010101010001100… |
… | …00011111001000011 |
3 | 1100221110121002010111 |
4 | 31111012003321003 |
5 | 213303003212201 |
6 | 10324115412151 |
7 | 1014451462555 |
oct | 152506037103 |
9 | 40843532114 |
10 | 14312554051 |
11 | 6085077774 |
12 | 29352b4057 |
13 | 14712b3bc3 |
14 | 99abd74d5 |
15 | 58b7c1b51 |
hex | 355183e43 |
14312554051 has 2 divisors, whose sum is σ = 14312554052. Its totient is φ = 14312554050.
The previous prime is 14312554033. The next prime is 14312554079. The reversal of 14312554051 is 15045521341.
It is a weak prime.
It is an emirp because it is prime and its reverse (15045521341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14312554051 - 27 = 14312553923 is a prime.
It is not a weakly prime, because it can be changed into another prime (14312584051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156277025 + 7156277026.
It is an arithmetic number, because the mean of its divisors is an integer number (7156277026).
Almost surely, 214312554051 is an apocalyptic number.
14312554051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312554051 is an equidigital number, since it uses as much as digits as its factorization.
14312554051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 14312554051 in words is "fourteen billion, three hundred twelve million, five hundred fifty-four thousand, fifty-one".
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