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143126213117497 is a prime number
BaseRepresentation
bin100000100010110000101011…
…000101110100011000111001
3200202202201202212202111110121
4200202300223011310120321
5122224434441024224442
61224223135151413241
742101345662243561
oct4042605305643071
9622681685674417
10143126213117497
1141671539015195
121407699b224221
1361b29896c153c
14274b4ba773da1
1511830943b9967
hex822c2b174639

143126213117497 has 2 divisors, whose sum is σ = 143126213117498. Its totient is φ = 143126213117496.

The previous prime is 143126213117431. The next prime is 143126213117501. The reversal of 143126213117497 is 794711312621341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141434434249641 + 1691778867856 = 11892621^2 + 1300684^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143126213117497 is a prime.

It is a super-2 number, since 2×1431262131174972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143126213114497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563106558748 + 71563106558749.

It is an arithmetic number, because the mean of its divisors is an integer number (71563106558749).

Almost surely, 2143126213117497 is an apocalyptic number.

It is an amenable number.

143126213117497 is a deficient number, since it is larger than the sum of its proper divisors (1).

143126213117497 is an equidigital number, since it uses as much as digits as its factorization.

143126213117497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1524096, while the sum is 52.

The spelling of 143126213117497 in words is "one hundred forty-three trillion, one hundred twenty-six billion, two hundred thirteen million, one hundred seventeen thousand, four hundred ninety-seven".