143126214010057 has 2 divisors, whose sum is σ = 143126214010058. Its totient is φ = 143126214010056.

The previous prime is 143126214010009. The next prime is 143126214010079. The reversal of 143126214010057 is 750010412621341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113232668695056 + 29893545315001 = 10641084^2 + 5467499^2 .

It is a cyclic number.

It is not a de Polignac number, because 143126214010057 - 2¹⁹ = 143126213485769 is a prime.

It is a super-2 number, since 2×143126214010057² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143126214009998 and 143126214010025.

It is not a weakly prime, because it can be changed into another prime (143126214010007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563107005028 + 71563107005029.

It is an arithmetic number, because the mean of its divisors is an integer number (71563107005029).

Almost surely, 2^{143126214010057} is an apocalyptic number.

It is an amenable number.

143126214010057 is a deficient number, since it is larger than the sum of its proper divisors (1).

143126214010057 is an equidigital number, since it uses as much as digits as its factorization.

143126214010057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 143126214010057 its reverse (750010412621341), we get a palindrome (893136626631398).

The spelling of 143126214010057 in words is "one hundred forty-three trillion, one hundred twenty-six billion, two hundred fourteen million, ten thousand, fifty-seven".