143126240004001 has 2 divisors, whose sum is σ = 143126240004002. Its totient is φ = 143126240004000.

The previous prime is 143126240003983. The next prime is 143126240004023. The reversal of 143126240004001 is 100400042621341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73250934872976 + 69875305131025 = 8558676^2 + 8359145^2 .

It is a cyclic number.

It is not a de Polignac number, because 143126240004001 - 2⁹ = 143126240003489 is a prime.

It is a super-3 number, since 3×143126240004001³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (143126240074001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563120002000 + 71563120002001.

It is an arithmetic number, because the mean of its divisors is an integer number (71563120002001).

Almost surely, 2^{143126240004001} is an apocalyptic number.

It is an amenable number.

143126240004001 is a deficient number, since it is larger than the sum of its proper divisors (1).

143126240004001 is an equidigital number, since it uses as much as digits as its factorization.

143126240004001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 143126240004001 its reverse (100400042621341), we get a palindrome (243526282625342).

The spelling of 143126240004001 in words is "one hundred forty-three trillion, one hundred twenty-six billion, two hundred forty million, four thousand, one".