143130040445043 has 24 divisors (see below), whose sum is σ = 220322282439168. Its totient is φ = 89329386938352.

The previous prime is 143130040445023. The next prime is 143130040445057. The reversal of 143130040445043 is 340544040031341.

143130040445043 is a `hidden beast` number, since 1 + 4 + 3 + 130 + 0 + 40 + 445 + 0 + 43 = 666.

It is not a de Polignac number, because 143130040445043 - 2²² = 143130036250739 is a prime.

It is a super-3 number, since 3×143130040445043³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143130040444989 and 143130040445007.

It is not an unprimeable number, because it can be changed into a prime (143130040445023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7355835705 + ... + 7355855162.

It is an arithmetic number, because the mean of its divisors is an integer number (9180095101632).

Almost surely, 2^{143130040445043} is an apocalyptic number.

143130040445043 is a deficient number, since it is larger than the sum of its proper divisors (77192241994125).

143130040445043 is a wasteful number, since it uses less digits than its factorization.

143130040445043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14711690943 (or 14711690940 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 36.

Adding to 143130040445043 its reverse (340544040031341), we get a palindrome (483674080476384).

The spelling of 143130040445043 in words is "one hundred forty-three trillion, one hundred thirty billion, forty million, four hundred forty-five thousand, forty-three".