1431300430130 has 16 divisors (see below), whose sum is σ = 2578663914840. Its totient is φ = 572003918592.

The previous prime is 1431300430121. The next prime is 1431300430141. The reversal of 1431300430130 is 310340031341.

It can be written as a sum of positive squares in 4 ways, for example, as 521083303321 + 910217126809 = 721861^2 + 954053^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1431300430096 and 1431300430105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64520039 + ... + 64542218.

Almost surely, 2^{1431300430130} is an apocalyptic number.

1431300430130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1431300430130 is a deficient number, since it is larger than the sum of its proper divisors (1147363484710).

1431300430130 is a wasteful number, since it uses less digits than its factorization.

1431300430130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129063373.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1431300430130 its reverse (310340031341), we get a palindrome (1741640461471).

The spelling of 1431300430130 in words is "one trillion, four hundred thirty-one billion, three hundred million, four hundred thirty thousand, one hundred thirty".