Base | Representation |
---|---|
bin | 11010101010001111… |
… | …10011011110100011 |
3 | 1100221111110022002111 |
4 | 31111013303132203 |
5 | 213303112323412 |
6 | 10324133300151 |
7 | 1014455405233 |
oct | 152507633643 |
9 | 40844408074 |
10 | 14313011107 |
11 | 608535a0aa |
12 | 2935494657 |
13 | 1471413c55 |
14 | 99acb5cc3 |
15 | 58b8622a7 |
hex | 3551f37a3 |
14313011107 has 2 divisors, whose sum is σ = 14313011108. Its totient is φ = 14313011106.
The previous prime is 14313011099. The next prime is 14313011171. The reversal of 14313011107 is 70111031341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14313011107 - 23 = 14313011099 is a prime.
It is not a weakly prime, because it can be changed into another prime (14313071107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156505553 + 7156505554.
It is an arithmetic number, because the mean of its divisors is an integer number (7156505554).
Almost surely, 214313011107 is an apocalyptic number.
14313011107 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313011107 is an equidigital number, since it uses as much as digits as its factorization.
14313011107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 14313011107 its reverse (70111031341), we get a palindrome (84424042448).
The spelling of 14313011107 in words is "fourteen billion, three hundred thirteen million, eleven thousand, one hundred seven".
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