14313011131 has 4 divisors (see below), whose sum is σ = 14555604600. Its totient is φ = 14070417664.

The previous prime is 14313011107. The next prime is 14313011171. The reversal of 14313011131 is 13111031341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14313011131 - 2⁵ = 14313011099 is a prime.

It is a super-2 number, since 2×14313011131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14313011099 and 14313011108.

It is not an unprimeable number, because it can be changed into a prime (14313011171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121296646 + ... + 121296763.

It is an arithmetic number, because the mean of its divisors is an integer number (3638901150).

Almost surely, 2^14313011131 is an apocalyptic number.

14313011131 is a deficient number, since it is larger than the sum of its proper divisors (242593469).

14313011131 is an equidigital number, since it uses as much as digits as its factorization.

14313011131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242593468.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 14313011131 its reverse (13111031341), we get a palindrome (27424042472).

The spelling of 14313011131 in words is "fourteen billion, three hundred thirteen million, eleven thousand, one hundred thirty-one".