1431304020133 has 36 divisors (see below), whose sum is σ = 1621502266692. Its totient is φ = 1262736034560.

The previous prime is 1431304020119. The next prime is 1431304020149. The reversal of 1431304020133 is 3310204031341.

It can be written as a sum of positive squares in 6 ways, for example, as 24938094724 + 1406365925409 = 157918^2 + 1185903^2 .

It is a de Polignac number, because none of the positive numbers 2^k-1431304020133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431304020098 and 1431304020107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431304020103) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 123456985 + ... + 123468577.

Almost surely, 2^{1431304020133} is an apocalyptic number.

1431304020133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1431304020133 is a deficient number, since it is larger than the sum of its proper divisors (190198246559).

1431304020133 is a wasteful number, since it uses less digits than its factorization.

1431304020133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13046 (or 13010 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1431304020133 its reverse (3310204031341), we get a palindrome (4741508051474).

The spelling of 1431304020133 in words is "one trillion, four hundred thirty-one billion, three hundred four million, twenty thousand, one hundred thirty-three".