Base | Representation |
---|---|
bin | 1101000001001000100100… |
… | …1010011010110010101010 |
3 | 1212200022200210110220012110 |
4 | 3100102021022122302222 |
5 | 3334001243323140132 |
6 | 50235210121423150 |
7 | 3005042521441146 |
oct | 320221112326252 |
9 | 55608623426173 |
10 | 14313132240042 |
11 | 4619190009229 |
12 | 1731b9303aab6 |
13 | 7ca95167579c |
14 | 376a8b720226 |
15 | 19c4b64311cc |
hex | d048929acaa |
14313132240042 has 16 divisors (see below), whose sum is σ = 28630169392032. Its totient is φ = 4770393261360.
The previous prime is 14313132240023. The next prime is 14313132240079. The reversal of 14313132240042 is 24004223131341.
It is a junction number, because it is equal to n+sod(n) for n = 14313132239991 and 14313132240009.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162657013 + ... + 162744984.
It is an arithmetic number, because the mean of its divisors is an integer number (1789385587002).
Almost surely, 214313132240042 is an apocalyptic number.
14313132240042 is an abundant number, since it is smaller than the sum of its proper divisors (14317037151990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14313132240042 is a wasteful number, since it uses less digits than its factorization.
14313132240042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 325409333.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 14313132240042 its reverse (24004223131341), we get a palindrome (38317355371383).
The spelling of 14313132240042 in words is "fourteen trillion, three hundred thirteen billion, one hundred thirty-two million, two hundred forty thousand, forty-two".
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