Base | Representation |
---|---|
bin | 1000010101001101001… |
… | …0101111110100000011 |
3 | 111200110001212122100202 |
4 | 2011103102233310003 |
5 | 4321113111003011 |
6 | 145430441235415 |
7 | 13224633231326 |
oct | 2052322576403 |
9 | 450401778322 |
10 | 143131344131 |
11 | 55779a04356 |
12 | 238a6492b6b |
13 | 10660542a49 |
14 | 6cdb4647bd |
15 | 3acaaac23b |
hex | 21534afd03 |
143131344131 has 2 divisors, whose sum is σ = 143131344132. Its totient is φ = 143131344130.
The previous prime is 143131344101. The next prime is 143131344199. The reversal of 143131344131 is 131443131341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143131344131 - 26 = 143131344067 is a prime.
It is a super-2 number, since 2×1431313441312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 143131344094 and 143131344103.
It is not a weakly prime, because it can be changed into another prime (143131344101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71565672065 + 71565672066.
It is an arithmetic number, because the mean of its divisors is an integer number (71565672066).
Almost surely, 2143131344131 is an apocalyptic number.
143131344131 is a deficient number, since it is larger than the sum of its proper divisors (1).
143131344131 is an equidigital number, since it uses as much as digits as its factorization.
143131344131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 143131344131 its reverse (131443131341), we get a palindrome (274574475472).
The spelling of 143131344131 in words is "one hundred forty-three billion, one hundred thirty-one million, three hundred forty-four thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •