1431314011122 has 8 divisors (see below), whose sum is σ = 2862628022256. Its totient is φ = 477104670372.

The previous prime is 1431314011097. The next prime is 1431314011151. The reversal of 1431314011122 is 2211104131341.

It is a sphenic number, since it is the product of 3 distinct primes.

1431314011122 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 1431314011092 and 1431314011101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119276167588 + ... + 119276167599.

It is an arithmetic number, because the mean of its divisors is an integer number (357828502782).

Almost surely, 2^{1431314011122} is an apocalyptic number.

1431314011122 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431314011122 is a wasteful number, since it uses less digits than its factorization.

1431314011122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 238552335192.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 1431314011122 its reverse (2211104131341), we get a palindrome (3642418142463).

The spelling of 1431314011122 in words is "one trillion, four hundred thirty-one billion, three hundred fourteen million, eleven thousand, one hundred twenty-two".