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14313161312011 is a prime number
BaseRepresentation
bin1101000001001000101011…
…1001010100011100001011
31212200022202211011220110001
43100102022321110130023
53334001323243441021
650235213040503431
73005043323523112
oct320221271243413
955608684156401
1014313161312011
1146191a5465451
121731ba091ab77
137ca9576b4233
14376a9152ac79
1519c4b8c75091
hexd048ae5470b

14313161312011 has 2 divisors, whose sum is σ = 14313161312012. Its totient is φ = 14313161312010.

The previous prime is 14313161311997. The next prime is 14313161312029. The reversal of 14313161312011 is 11021316131341.

It is a weak prime.

It is an emirp because it is prime and its reverse (11021316131341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14313161312011 - 29 = 14313161311499 is a prime.

It is not a weakly prime, because it can be changed into another prime (14313161312081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156580656005 + 7156580656006.

It is an arithmetic number, because the mean of its divisors is an integer number (7156580656006).

Almost surely, 214313161312011 is an apocalyptic number.

14313161312011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313161312011 is an equidigital number, since it uses as much as digits as its factorization.

14313161312011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 28.

Adding to 14313161312011 its reverse (11021316131341), we get a palindrome (25334477443352).

The spelling of 14313161312011 in words is "fourteen trillion, three hundred thirteen billion, one hundred sixty-one million, three hundred twelve thousand, eleven".