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143132201110126 = 2312308583888873
BaseRepresentation
bin100000100010110110010000…
…000000001100101001101110
3200202210022020012020001010101
4200202312100000030221232
5122230034221441011001
61224230005255101314
742101650242322204
oct4042662000145156
9622708205201111
10143132201110126
1141674031094728
1214077b9067183a
1361b3402144b47
14274b8c7b39074
1511832e4e2ea01
hex822d9000ca6e

143132201110126 has 8 divisors (see below), whose sum is σ = 221624053331904. Its totient is φ = 69257516666160.

The previous prime is 143132201110069. The next prime is 143132201110163. The reversal of 143132201110126 is 621011102231341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 143132201110094 and 143132201110103.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1154291944375 + ... + 1154291944498.

It is an arithmetic number, because the mean of its divisors is an integer number (27703006666488).

Almost surely, 2143132201110126 is an apocalyptic number.

143132201110126 is a deficient number, since it is larger than the sum of its proper divisors (78491852221778).

143132201110126 is a wasteful number, since it uses less digits than its factorization.

143132201110126 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2308583888906.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 143132201110126 its reverse (621011102231341), we get a palindrome (764143303341467).

The spelling of 143132201110126 in words is "one hundred forty-three trillion, one hundred thirty-two billion, two hundred one million, one hundred ten thousand, one hundred twenty-six".

Divisors: 1 2 31 62 2308583888873 4617167777746 71566100555063 143132201110126