Base | Representation |
---|---|
bin | 1000010101001101100… |
… | …1001100011101100101 |
3 | 111200110012001111220010 |
4 | 2011103121030131211 |
5 | 4321114024044331 |
6 | 145430541400433 |
7 | 13224653501133 |
oct | 2052331143545 |
9 | 450405044803 |
10 | 143133034341 |
11 | 5577a959220 |
12 | 238a6b69119 |
13 | 106609b517b |
14 | 6cdb784753 |
15 | 3acace2e46 |
hex | 215364c765 |
143133034341 has 16 divisors (see below), whose sum is σ = 208298377728. Its totient is φ = 86703596400.
The previous prime is 143133034339. The next prime is 143133034351. The reversal of 143133034341 is 143430331341.
It is not a de Polignac number, because 143133034341 - 21 = 143133034339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143133034299 and 143133034308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143133034351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1025865 + ... + 1157006.
It is an arithmetic number, because the mean of its divisors is an integer number (13018648608).
Almost surely, 2143133034341 is an apocalyptic number.
143133034341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
143133034341 is a deficient number, since it is larger than the sum of its proper divisors (65165343387).
143133034341 is a wasteful number, since it uses less digits than its factorization.
143133034341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2184872.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 143133034341 its reverse (143430331341), we get a palindrome (286563365682).
The spelling of 143133034341 in words is "one hundred forty-three billion, one hundred thirty-three million, thirty-four thousand, three hundred forty-one".
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