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143133204013 = 19109315594421
BaseRepresentation
bin1000010101001101100…
…1110101111000101101
3111200110012101010122021
42011103121311320231
54321114100012023
6145430545150141
713224655105612
oct2052331657055
9450405333567
10143133204013
115577aa64748
12238a702b351
1310660a44477
146cdb7ca509
153acad2835d
hex2153675e2d

143133204013 has 16 divisors (see below), whose sum is σ = 150935241600. Its totient is φ = 135358292160.

The previous prime is 143133203989. The next prime is 143133204047. The reversal of 143133204013 is 310402331341.

It is not a de Polignac number, because 143133204013 - 25 = 143133203981 is a prime.

It is a super-2 number, since 2×1431332040132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143133204713) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32373543 + ... + 32377963.

It is an arithmetic number, because the mean of its divisors is an integer number (9433452600).

Almost surely, 2143133204013 is an apocalyptic number.

It is an amenable number.

143133204013 is a deficient number, since it is larger than the sum of its proper divisors (7802037587).

143133204013 is a wasteful number, since it uses less digits than its factorization.

143133204013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7092.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 143133204013 its reverse (310402331341), we get a palindrome (453535535354).

The spelling of 143133204013 in words is "one hundred forty-three billion, one hundred thirty-three million, two hundred four thousand, thirteen".

Divisors: 1 19 1093 1559 4421 20767 29621 83999 1703987 4832153 6892339 32375753 91810907 130954441 7533326527 143133204013