Base | Representation |
---|---|
bin | 11010101010010010… |
… | …00001100110110001 |
3 | 1100221112001120001212 |
4 | 31111021001212301 |
5 | 213303203043441 |
6 | 10324144205505 |
7 | 1014461210225 |
oct | 152511014661 |
9 | 40845046055 |
10 | 14313331121 |
11 | 6085558581 |
12 | 2935609895 |
13 | 14714c67cb |
14 | 99ad5a785 |
15 | 58b8c6eeb |
hex | 3552419b1 |
14313331121 has 2 divisors, whose sum is σ = 14313331122. Its totient is φ = 14313331120.
The previous prime is 14313331099. The next prime is 14313331127. The reversal of 14313331121 is 12113331341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8527599025 + 5785732096 = 92345^2 + 76064^2 .
It is an emirp because it is prime and its reverse (12113331341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14313331121 - 214 = 14313314737 is a prime.
It is not a weakly prime, because it can be changed into another prime (14313331127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156665560 + 7156665561.
It is an arithmetic number, because the mean of its divisors is an integer number (7156665561).
Almost surely, 214313331121 is an apocalyptic number.
It is an amenable number.
14313331121 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313331121 is an equidigital number, since it uses as much as digits as its factorization.
14313331121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 23.
Adding to 14313331121 its reverse (12113331341), we get a palindrome (26426662462).
The spelling of 14313331121 in words is "fourteen billion, three hundred thirteen million, three hundred thirty-one thousand, one hundred twenty-one".
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