14313400431341 has 4 divisors (see below), whose sum is σ = 15614618652384. Its totient is φ = 13012182210300.

The previous prime is 14313400431311. The next prime is 14313400431389.

14313400431341 is nontrivially palindromic in base 10.

14313400431341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14313400431341 - 2¹⁸ = 14313400169197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14313400431298 and 14313400431307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14313400431311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650609110505 + ... + 650609110526.

It is an arithmetic number, because the mean of its divisors is an integer number (3903654663096).

Almost surely, 2^{14313400431341} is an apocalyptic number.

14313400431341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14313400431341 is a deficient number, since it is larger than the sum of its proper divisors (1301218221043).

14313400431341 is a wasteful number, since it uses less digits than its factorization.

14313400431341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1301218221042.

The product of its (nonzero) digits is 20736, while the sum is 32.

It can be divided in two parts, 14313400 and 431341, that added together give a palindrome (14744741).

The spelling of 14313400431341 in words is "fourteen trillion, three hundred thirteen billion, four hundred million, four hundred thirty-one thousand, three hundred forty-one".