14313443400233 has 2 divisors, whose sum is σ = 14313443400234. Its totient is φ = 14313443400232.

The previous prime is 14313443400131. The next prime is 14313443400239. The reversal of 14313443400233 is 33200434431341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13791916780009 + 521526620224 = 3713747^2 + 722168^2 .

It is an emirp because it is prime and its reverse (33200434431341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14313443400233 - 2¹⁴ = 14313443383849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14313443400193 and 14313443400202.

It is not a weakly prime, because it can be changed into another prime (14313443400239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156721700116 + 7156721700117.

It is an arithmetic number, because the mean of its divisors is an integer number (7156721700117).

Almost surely, 2^{14313443400233} is an apocalyptic number.

It is an amenable number.

14313443400233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313443400233 is an equidigital number, since it uses as much as digits as its factorization.

14313443400233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 14313443400233 its reverse (33200434431341), we get a palindrome (47513877831574).

The spelling of 14313443400233 in words is "fourteen trillion, three hundred thirteen billion, four hundred forty-three million, four hundred thousand, two hundred thirty-three".