Base | Representation |
---|---|
bin | 11010101010010011… |
… | …00001110100001011 |
3 | 1100221112022021001011 |
4 | 31111021201310023 |
5 | 213303221304201 |
6 | 10324151104351 |
7 | 1014462266656 |
oct | 152511416413 |
9 | 40845267034 |
10 | 14313463051 |
11 | 6085638708 |
12 | 29356720b7 |
13 | 1471541884 |
14 | 99ad9289d |
15 | 58b901151 |
hex | 355261d0b |
14313463051 has 2 divisors, whose sum is σ = 14313463052. Its totient is φ = 14313463050.
The previous prime is 14313463037. The next prime is 14313463057. The reversal of 14313463051 is 15036431341.
It is a strong prime.
It is an emirp because it is prime and its reverse (15036431341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14313463051 - 215 = 14313430283 is a prime.
It is not a weakly prime, because it can be changed into another prime (14313463057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156731525 + 7156731526.
It is an arithmetic number, because the mean of its divisors is an integer number (7156731526).
Almost surely, 214313463051 is an apocalyptic number.
14313463051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313463051 is an equidigital number, since it uses as much as digits as its factorization.
14313463051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 14313463051 its reverse (15036431341), we get a palindrome (29349894392).
The spelling of 14313463051 in words is "fourteen billion, three hundred thirteen million, four hundred sixty-three thousand, fifty-one".
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