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143141034111 = 347713678037
BaseRepresentation
bin1000010101001111011…
…1101101100001111111
3111200110202002221111220
42011103313231201333
54321123101042421
6145431425044423
713225111500105
oct2052367554177
9450422087456
10143141034111
11557844225a9
12238a9786713
131066255646a
146cdc867c75
153acb8733c6
hex2153ded87f

143141034111 has 4 divisors (see below), whose sum is σ = 190854712152. Its totient is φ = 95427356072.

The previous prime is 143141034097. The next prime is 143141034151. The reversal of 143141034111 is 111430141341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143141034111 - 27 = 143141033983 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143141034151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23856839016 + ... + 23856839021.

It is an arithmetic number, because the mean of its divisors is an integer number (47713678038).

Almost surely, 2143141034111 is an apocalyptic number.

143141034111 is a deficient number, since it is larger than the sum of its proper divisors (47713678041).

143141034111 is an equidigital number, since it uses as much as digits as its factorization.

143141034111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47713678040.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 143141034111 its reverse (111430141341), we get a palindrome (254571175452).

The spelling of 143141034111 in words is "one hundred forty-three billion, one hundred forty-one million, thirty-four thousand, one hundred eleven".

Divisors: 1 3 47713678037 143141034111