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14314203041 is a prime number
BaseRepresentation
bin11010101010011000…
…10110011110100001
31100221120200212010012
431111030112132201
5213303413444131
610324215014305
71014501501245
oct152514263641
940846625105
1014314203041
116085aa3676
12293596a395
131471740638
1499b106425
1558b9ea52b
hex3553167a1

14314203041 has 2 divisors, whose sum is σ = 14314203042. Its totient is φ = 14314203040.

The previous prime is 14314203011. The next prime is 14314203077. The reversal of 14314203041 is 14030241341.

14314203041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11814603025 + 2499600016 = 108695^2 + 49996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14314203041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14314202998 and 14314203016.

It is not a weakly prime, because it can be changed into another prime (14314203011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157101520 + 7157101521.

It is an arithmetic number, because the mean of its divisors is an integer number (7157101521).

Almost surely, 214314203041 is an apocalyptic number.

It is an amenable number.

14314203041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14314203041 is an equidigital number, since it uses as much as digits as its factorization.

14314203041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14314203041 its reverse (14030241341), we get a palindrome (28344444382).

The spelling of 14314203041 in words is "fourteen billion, three hundred fourteen million, two hundred three thousand, forty-one".