Base | Representation |
---|---|
bin | 11010101010011000… |
… | …10110100000000011 |
3 | 1100221120200212020211 |
4 | 31111030112200003 |
5 | 213303414000024 |
6 | 10324215014551 |
7 | 1014501501445 |
oct | 152514264003 |
9 | 40846625224 |
10 | 14314203139 |
11 | 6085aa3755 |
12 | 293596a457 |
13 | 14717406b2 |
14 | 99b106495 |
15 | 58b9ea594 |
hex | 355316803 |
14314203139 has 2 divisors, whose sum is σ = 14314203140. Its totient is φ = 14314203138.
The previous prime is 14314203121. The next prime is 14314203149. The reversal of 14314203139 is 93130241341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14314203139 - 25 = 14314203107 is a prime.
It is a super-3 number, since 3×143142031393 (a number of 31 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14314203139.
It is not a weakly prime, because it can be changed into another prime (14314203149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157101569 + 7157101570.
It is an arithmetic number, because the mean of its divisors is an integer number (7157101570).
Almost surely, 214314203139 is an apocalyptic number.
14314203139 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314203139 is an equidigital number, since it uses as much as digits as its factorization.
14314203139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 14314203139 in words is "fourteen billion, three hundred fourteen million, two hundred three thousand, one hundred thirty-nine".
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