Base | Representation |
---|---|
bin | 10100110101000111011… |
… | …101110100111110111111 |
3 | 12001211202100010020021121 |
4 | 110311013131310332333 |
5 | 141423023304023403 |
6 | 3013330421011411 |
7 | 205262666455606 |
oct | 24650735647677 |
9 | 5054670106247 |
10 | 1431423111103 |
11 | 5020770357a7 |
12 | 1b1504853b67 |
13 | a4ca0a7cc3b |
14 | 4d3d1a60a3d |
15 | 2737bb963bd |
hex | 14d47774fbf |
1431423111103 has 4 divisors (see below), whose sum is σ = 1439419888440. Its totient is φ = 1423426333768.
The previous prime is 1431423111061. The next prime is 1431423111191. The reversal of 1431423111103 is 3011113241341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1431423111103 - 213 = 1431423102911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1431420111103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3998388400 + ... + 3998388757.
It is an arithmetic number, because the mean of its divisors is an integer number (359854972110).
Almost surely, 21431423111103 is an apocalyptic number.
1431423111103 is a deficient number, since it is larger than the sum of its proper divisors (7996777337).
1431423111103 is an equidigital number, since it uses as much as digits as its factorization.
1431423111103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7996777336.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1431423111103 its reverse (3011113241341), we get a palindrome (4442536352444).
The spelling of 1431423111103 in words is "one trillion, four hundred thirty-one billion, four hundred twenty-three million, one hundred eleven thousand, one hundred three".
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