Base | Representation |
---|---|
bin | 100000100010111111110110… |
… | …100011010000101000100001 |
3 | 200202211021211202001201201001 |
4 | 200202333312203100220201 |
5 | 122230221330421341342 |
6 | 1224234432330512001 |
7 | 42102463606306156 |
oct | 4042776643205041 |
9 | 622737752051631 |
10 | 143142511512097 |
11 | 41678442038299 |
12 | 14079b89595601 |
13 | 61b4386232906 |
14 | 274c1c51bc22d |
15 | 11836ea1a38b7 |
hex | 822ff68d0a21 |
143142511512097 has 2 divisors, whose sum is σ = 143142511512098. Its totient is φ = 143142511512096.
The previous prime is 143142511511941. The next prime is 143142511512109. The reversal of 143142511512097 is 790215115241341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 99777244188736 + 43365267323361 = 9988856^2 + 6585231^2 .
It is a cyclic number.
It is not a de Polignac number, because 143142511512097 - 231 = 143140364028449 is a prime.
It is not a weakly prime, because it can be changed into another prime (143142511542097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71571255756048 + 71571255756049.
It is an arithmetic number, because the mean of its divisors is an integer number (71571255756049).
Almost surely, 2143142511512097 is an apocalyptic number.
It is an amenable number.
143142511512097 is a deficient number, since it is larger than the sum of its proper divisors (1).
143142511512097 is an equidigital number, since it uses as much as digits as its factorization.
143142511512097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 46.
The spelling of 143142511512097 in words is "one hundred forty-three trillion, one hundred forty-two billion, five hundred eleven million, five hundred twelve thousand, ninety-seven".
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