Base | Representation |
---|---|
bin | 1101000001001101000000… |
… | …1110010010000111001011 |
3 | 1212200102202212210200210012 |
4 | 3100103100032102013023 |
5 | 3334011214023413103 |
6 | 50235524310342135 |
7 | 3005114206102316 |
oct | 320232016220713 |
9 | 55612685720705 |
10 | 14314324435403 |
11 | 4619741a74253 |
12 | 173226635a94b |
13 | 7caab1666725 |
14 | 376b61bbb97d |
15 | 19c535e292d8 |
hex | d04d03921cb |
14314324435403 has 2 divisors, whose sum is σ = 14314324435404. Its totient is φ = 14314324435402.
The previous prime is 14314324435391. The next prime is 14314324435417. The reversal of 14314324435403 is 30453442341341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14314324435403 - 226 = 14314257326539 is a prime.
It is not a weakly prime, because it can be changed into another prime (14314324435493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157162217701 + 7157162217702.
It is an arithmetic number, because the mean of its divisors is an integer number (7157162217702).
Almost surely, 214314324435403 is an apocalyptic number.
14314324435403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314324435403 is an equidigital number, since it uses as much as digits as its factorization.
14314324435403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 829440, while the sum is 41.
Adding to 14314324435403 its reverse (30453442341341), we get a palindrome (44767766776744).
The spelling of 14314324435403 in words is "fourteen trillion, three hundred fourteen billion, three hundred twenty-four million, four hundred thirty-five thousand, four hundred three".
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