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14314739815513 is a prime number
BaseRepresentation
bin1101000001001110100011…
…1110110101010001011001
31212200110211211102012011201
43100103220332311101121
53334013041343044023
650240033425354201
73005130411552124
oct320235076652131
955613754365151
1014314739815513
1146199354944a5
121732361498961
137cab49731687
14376ba10273bb
1519c55c629bad
hexd04e8fb5459

14314739815513 has 2 divisors, whose sum is σ = 14314739815514. Its totient is φ = 14314739815512.

The previous prime is 14314739815501. The next prime is 14314739815529. The reversal of 14314739815513 is 31551893741341.

14314739815513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9517798818649 + 4796940996864 = 3085093^2 + 2190192^2 .

It is a cyclic number.

It is not a de Polignac number, because 14314739815513 - 225 = 14314706261081 is a prime.

It is not a weakly prime, because it can be changed into another prime (14314739815613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157369907756 + 7157369907757.

It is an arithmetic number, because the mean of its divisors is an integer number (7157369907757).

Almost surely, 214314739815513 is an apocalyptic number.

It is an amenable number.

14314739815513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14314739815513 is an equidigital number, since it uses as much as digits as its factorization.

14314739815513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5443200, while the sum is 55.

The spelling of 14314739815513 in words is "fourteen trillion, three hundred fourteen billion, seven hundred thirty-nine million, eight hundred fifteen thousand, five hundred thirteen".