Base | Representation |
---|---|
bin | 11010101010100001… |
… | …00111011100111001 |
3 | 1100221122210122212110 |
4 | 31111100213130321 |
5 | 213304210234040 |
6 | 10324255002533 |
7 | 1014514136106 |
oct | 152520473471 |
9 | 40848718773 |
10 | 14315321145 |
11 | 6086697724 |
12 | 2936209449 |
13 | 1471a42538 |
14 | 99b317aad |
15 | 58bb6b980 |
hex | 355427739 |
14315321145 has 32 divisors (see below), whose sum is σ = 24380956800. Its totient is φ = 7151721984.
The previous prime is 14315321131. The next prime is 14315321159. The reversal of 14315321145 is 54112351341.
It is an interprime number because it is at equal distance from previous prime (14315321131) and next prime (14315321159).
It is not a de Polignac number, because 14315321145 - 24 = 14315321129 is a prime.
It is a super-2 number, since 2×143153211452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 256822 + ... + 307551.
It is an arithmetic number, because the mean of its divisors is an integer number (761904900).
Almost surely, 214315321145 is an apocalyptic number.
14315321145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14315321145 is a deficient number, since it is larger than the sum of its proper divisors (10065635655).
14315321145 is a wasteful number, since it uses less digits than its factorization.
14315321145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 564489.
The product of its digits is 7200, while the sum is 30.
Adding to 14315321145 its reverse (54112351341), we get a palindrome (68427672486).
The spelling of 14315321145 in words is "fourteen billion, three hundred fifteen million, three hundred twenty-one thousand, one hundred forty-five".
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