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14315404601 is a prime number
BaseRepresentation
bin11010101010100001…
…11011110100111001
31100221122221220100102
431111100323310321
5213304220421401
610324300445145
71014514634321
oct152520736471
940848856312
1014315404601
1160867443a3
1229362497b5
131471a71514
1499b33a281
1558bb8656b
hex35543bd39

14315404601 has 2 divisors, whose sum is σ = 14315404602. Its totient is φ = 14315404600.

The previous prime is 14315404559. The next prime is 14315404613. The reversal of 14315404601 is 10640451341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9697522576 + 4617882025 = 98476^2 + 67955^2 .

It is a cyclic number.

It is not a de Polignac number, because 14315404601 - 210 = 14315403577 is a prime.

It is a super-3 number, since 3×143154046013 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14315404681) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157702300 + 7157702301.

It is an arithmetic number, because the mean of its divisors is an integer number (7157702301).

Almost surely, 214315404601 is an apocalyptic number.

It is an amenable number.

14315404601 is a deficient number, since it is larger than the sum of its proper divisors (1).

14315404601 is an equidigital number, since it uses as much as digits as its factorization.

14315404601 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 14315404601 its reverse (10640451341), we get a palindrome (24955855942).

The spelling of 14315404601 in words is "fourteen billion, three hundred fifteen million, four hundred four thousand, six hundred one".