Base | Representation |
---|---|
bin | 10100110101001111001… |
… | …110110111010111001100 |
3 | 12001212002102021220211210 |
4 | 110311033032313113030 |
5 | 141423310133001122 |
6 | 3013351353414420 |
7 | 205266141116403 |
oct | 24651716672714 |
9 | 5055072256753 |
10 | 1431553406412 |
11 | 502133639578 |
12 | 1b154040a410 |
13 | a4cc1a6cc5c |
14 | 4d40509a63a |
15 | 2738833240c |
hex | 14d4f3b75cc |
1431553406412 has 48 divisors (see below), whose sum is σ = 3419627016960. Its totient is φ = 465861536448.
The previous prime is 1431553406401. The next prime is 1431553406417. The reversal of 1431553406412 is 2146043551341.
It is not an unprimeable number, because it can be changed into a prime (1431553406417) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 397153 + ... + 1738055.
It is an arithmetic number, because the mean of its divisors is an integer number (71242229520).
Almost surely, 21431553406412 is an apocalyptic number.
1431553406412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1431553406412 is an abundant number, since it is smaller than the sum of its proper divisors (1988073610548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1431553406412 is a wasteful number, since it uses less digits than its factorization.
1431553406412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1343022 (or 1343020 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 1431553406412 its reverse (2146043551341), we get a palindrome (3577596957753).
The spelling of 1431553406412 in words is "one trillion, four hundred thirty-one billion, five hundred fifty-three million, four hundred six thousand, four hundred twelve".
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